Voltage Gain Enhancement for Step-Up Converter Constructed by KY and Buck-Boost Converters

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By Jackson Taylor

Simulation diagram
YouTube video

SIMULATION

DESIGN

  • POWER =60W
  • VIN=12V
  • VOUT=72V

· Lm =148μH, Lk = 0.3μH

· the turns ratio of coupled inductor n = Ns/Np =3

· OPERATING FREQUENCY OF THE SWITCH (MOSFET HERE) =100KHz

· Gain formula of converter = ( (2‑D) / (1‑D) )+n

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OUTPUT CURRENT

IOUT = POUT / VOUT
IOUT = 60W / 72V
IOUT = 0.833A

INPUT CURRENT

Assume that the converter efficiency is about 100%
POUT = PIN

IOUT = PIN / VIN
IOUT = 60W / 12V
IOUT = 5A

VOLTAGE GAIN CALCULATION

Gain = VOUT / VIN
VIN = 12V
VOUT = 72V
Gain = 72V / 12V

Gain = 6

DUTY CYCLE CALCULATION

Voltage gain of converter = ( (2‑D) / (1‑D) )+n
6 = ( (2‑D) / (1‑D) )+3
3 = (2‑D) / (1‑D)
3(1‑D) = 2‑D
3‑3D = 2‑D
1 = 2D
D = 0.5
D = 50 %

Coupling coefficient calculation

We have,
The coupling coefficient of coupled inductor, k = Lm / (Lm + Lk)
Lm =148μH, Lk = 0.3μH
K = 148μH / (148μH + 0.3μH) = 0.997

COUPLED INDUCTOR DESIGN

Here core used is ETD‑59. From the datasheet of ETD‑59 core
AL = 4.7 µH

We have,
Mutual inductance = k √LP · LS = 148 µH
Winding ratio ≈ 1:3
Let N be turns in primary, 3N in secondary
LP = N² AL
LS = (3N)² AL = 9N² AL
M = k √9N⁴ AL² = k · 3N² AL
148 µH = 0.997 · 3N² · 4.7 µH
N² = 148 µH / 14.05 µH = 10.53
N ≈ 3.24 ≈ 3

No. of turns in primary = 3

No. of turns in secondary = 3N = 3 · 3

No. of turns in secondary = 9

LP = NP² · AL = 9 · 4.7 µH

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LP = 42.3 µH

LS = NS² · AL = 9² · 4.7 µH = 81 · 4.7 µH

LS = 380 µH

OUTPUT CAPACITOR VALUE

For a capacitor: I = C · dV/dt
Assume ripple dV = 0.01 % · 72 V = 0.0072 V
dt = D / f (duty / frequency)
C = I·D / (f·dV)
C = 0.833 A · 0.5 / (100 000 Hz · 0.0072 V) ≈ 578 µF → use standard 470 µF

Hardware

Hardware photo 1 Hardware photo 2 Hardware photo 3

WAVE FORMS

Waveform 1

Figure: PWM waveform (open‑loop)

Waveform 2

Figure: PWM waveform (closed‑loop)

PROGRAM (OPEN LOOP)

//Micro controller - dspic30f2010
//Compiler - mikroc
//Crystal frequency = 20 MHz
//Output frequency = 50 kHz
// //duty_50% = (clock_frequency/ (output_frequency*4 *1)) -1 =99
//DEAD TIME = duty_50%/2 =45
void main()
{
    unsigned int pwm_period, current_duty;
    current_duty = 99;               // duty ratio 50 % = 99
    pwm_period = PWM1_MC_Init(50000, 0, 0x11, 0);   // enable 1L AND 1H PWM pins
    PWM1_MC_Set_Duty(current_duty, 1);
    PWM1_MC_Start();
    DTCON1 = 10;   // DEAD TIME CONTROL (max 79)
    while (1);
}

PROGRAM (CLOSED LOOP)

//Crystal frequency = 20 MHz
//Output frequency = 50 kHz
// //duty_50% = (clock_frequency/ (output_frequency*4 *1)) -1 =99
//DEAD TIME = duty_50%/2 =45
//Feedback network: 100 kΩ & 2.2 kΩ
//ADC reference value = 295 for 67 V
int feedbackvoltage;
void main()
{
    unsigned int pwm_period, current_duty;
    current_duty = 99;                // duty ratio 50 % = 99
    pwm_period = PWM1_MC_Init(50000, 0, 0x11, 0);   // enable 1L AND 1H PWM pins
    PWM1_MC_Set_Duty(current_duty, 1);
    PWM1_MC_Start();
    DTCON1 = 10;     // DEAD TIME CONTROL (max 79)
    //UART1_Init(9600);               // Initialise UART at 9600 bps
    //Delay_ms(100);
    //UART_Write_Text("Start");
    //UART_Write(0xd);
    TRISB.F0 = 1;
    while (1)
    {
        feedbackvoltage = ADC1_Read(0) * 67 / 295;  Delay_ms(10);
        //adctoascii(); UART_Write_Text(g); UART_Write(0xd);
        //Delay_ms(100);
        if (feedbackvoltage > 70)
        {
            current_duty = current_duty - 1;
            if (current_duty < 1) current_duty = 0;
            PWM1_MC_Set_Duty(current_duty, 1);
        }
        else if (feedbackvoltage < 69)
        {
            current_duty = current_duty + 1;
            if (current_duty > 160) current_duty = 160;
            PWM1_MC_Set_Duty(current_duty, 1);
        }
    }
}
See also
3 LEVEL FULL BRIDGE INVERTER SIMULATION IN MATLAB

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